Can anyone help me answer this question...
Find the area of a right isoscles triangle if the altitude on the hypotenuse is 4 cm.
A right isosceles triangle has two 45 degree angles and is half of a square, divided along a diagonal. The altitude on the hypotenuse (4) is half the hypotenuse, so the hypotenuse is 8. The area is
A = (1/2)*4*8 = 16