Suppose a basketball player is an excellent free throw shooter and makes 91% of his free throws (i.e., he has a 91% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player shoots five free throws. Find the probability that he makes all five throws. A).0 B).0.376 C).0.624 D).1
The probability of all events occurring is found by multiplying the values of the individual events.
Probability = .91^5 = ?
To find the probability that the player makes all five throws, we can simply multiply the probability of making each individual throw together, since the throws are independent events.
The probability of making a single free throw is given as 91%, or 0.91. Therefore, the probability of missing a single free throw is 1 - 0.91 = 0.09.
To calculate the probability of making all five throws, we can raise 0.91 to the power of 5, since each throw has the same probability.
P(making all five throws) = (0.91)^5
Calculating this expression, we find that the probability is approximately 0.624.
Therefore, the correct answer is C) 0.624