I need to know how many calories to warm 58ml of water from 10 degress C to 100 degress C and vaporize it at 100 degress C.
To calculate the number of calories required to warm 58ml of water from 10 degrees Celsius to 100 degrees Celsius and vaporize it at 100 degrees Celsius, you can follow these steps:
1. Calculate the heat required to warm the water from the initial temperature (10°C) to the boiling point (100°C). The specific heat capacity of water is approximately 1 calorie/gram°C.
- Mass of water = volume × density
- Density of water = 1 gram/ml
- Mass of water = 58 ml × 1 gram/ml = 58 grams
- Heat required to warm water = Mass × specific heat capacity × temperature change
- Heat required = 58 grams × 1 calorie/gram°C × (100°C - 10°C)
2. Calculate the heat required to vaporize the water at its boiling point (100°C). The heat of vaporization of water is approximately 540 calories/gram.
- Heat required to vaporize water = Mass × heat of vaporization
- Heat required = 58 grams × 540 calories/gram
3. Sum up the two heats calculated in steps 1 and 2 to get the total heat required.
- Total heat required = Heat required to warm water + Heat required to vaporize water
By following these steps, you can calculate the total number of calories required to warm and vaporize 58ml of water from 10 degrees Celsius to 100 degrees Celsius.