with an average acceleration of -0.50 m/s^2, ho wlong will it take a cyclist to bring a bicycle with an intitial speeed of 13.5 m/s to a complete stop?
27 seconds
To find the time it takes for the cyclist to bring the bicycle to a complete stop, you can use the equation:
v = u + at
Where:
v = final velocity (which is 0 m/s as the bicycle comes to a stop)
u = initial velocity (13.5 m/s)
a = average acceleration (-0.50 m/s^2)
t = time
Rearranging the equation to solve for time (t):
t = (v - u) / a
Substituting the values:
t = (0 - 13.5) / (-0.50)
Calculating this:
t = (-13.5) / (-0.50)
t = 27 seconds
Therefore, it will take the cyclist 27 seconds to bring the bicycle to a complete stop.
To find out how long it will take for the cyclist to bring the bicycle to a complete stop, we can use the equation of motion:
v = u + at
Where:
v is the final velocity (which is 0 m/s because the bicycle comes to a complete stop)
u is the initial velocity (which is 13.5 m/s)
a is the acceleration (which is -0.50 m/s^2)
t is the time it takes to bring the bicycle to a stop (what we need to find)
Let's plug in the values we have:
0 = 13.5 + (-0.50)t
To solve for t, we'll rearrange the equation:
-0.50t = -13.5
Now, let's solve for t by dividing both sides of the equation by -0.50:
t = -13.5 / -0.50
Simplifying the equation further:
t = 27
Therefore, it will take the cyclist 27 seconds to bring the bicycle to a complete stop with an average acceleration of -0.50 m/s^2.
V = Vo - 0.50 t = 0
t = Vo /0.50
13.5/0.5 = ___ seconds