The cost in millions to remove x% of pollution in a lake modeled by
C=6000/200-2x.
What is the cost to remove 75% of the pollutant?
What is the cost to remove 99% of the pollutant?
For what value is this equation undefined?
C=6000/(200-2X) I'LL ASSUME THIS IS THE EQUATION.
C=6000/(200-2*75)
C=6000/(200-150)
C=6000/50
C=120 COST TO REMOVE 75%.
C=6000/(200-2*90)
C=6000/(200-180)
C=6000/20
C=300 COST TO REMOVE 90%.
C=6000/(200-2*99)
C=6000/(200-198)
C=6000/2
C=3000 COST TO REMOVE 99%.
THE EQUATION IS UNDEFINED WHEN YOU USE 100%.
C=6000/(200-200)
C=6000/0 C BECOMES UNDEFINED WHEN YOU DIVIDE BY 0.
To find the cost to remove a certain percentage of the pollutant, we can substitute that percentage into the given equation and solve for C.
1. Cost to remove 75% of the pollutant:
Substitute x = 75 into the equation:
C = 6000 / (200 - 2(75))
C = 6000 / (200 - 150)
C = 6000 / 50
C = 120
Therefore, the cost to remove 75% of the pollutant is 120 million.
2. Cost to remove 99% of the pollutant:
Substitute x = 99 into the equation:
C = 6000 / (200 - 2(99))
C = 6000 / (200 - 198)
C = 6000 / 2
C = 3000
Therefore, the cost to remove 99% of the pollutant is 3000 million.
3. For what value is this equation undefined?
The equation C = 6000 / (200 - 2x) is undefined when the denominator (200 - 2x) equals zero. To find the value of x that makes this happen, we solve the equation 200 - 2x = 0:
200 - 2x = 0
2x = 200
x = 200/2
x = 100
Thus, the equation is undefined for x = 100.