x^2+y^2=625

Find an equation of the line that is tangent to the circle at this point.

1 answer

what point?

Similar Questions

The point P = (4, 3) lies on the circle x2 + y2 = 25. Find an equation for the line that is tangent to the circle at P. This

Top answer: Why did the circle go to the dentist? Because it needed a tangent! Now, let's find that tangent Read more.
The point P = (4, 3) lies on the circle x2 + y2 = 25. Find an equation for the line that is tangent to the circle at P. This

Top answer: http://www.jiskha.com/display.cgi?id=1492718754 Read more.
The tangent to a circle may be defined as the line that intersects the circle in a single point, called the point of tangency.

Top answer: sub y = mx + b into x^2 + y^2 = r^2 expanding gave me x^2 + m^2x^2 + 2bmx + b^2 - r^2 = 0 a^2(1+m^2) Read more.
Line l is tangent to circle O at point P(3,4) where the center is located at (0,0).a. Find the radius of the circle. (I got 4)

Top answer: Since the line is tangent at a point to the circle, then the point lies on the circle. Also, since Read more.
how to find if line rp is tangent to circle 0 at p, and the circle bisects 0r at point m. if tangent segment rp has a length of

Top answer: To determine if line RP is tangent to circle O at point P, and if circle O bisects line OR at point Read more.
Answer check please: Consider the circle (x-3)^2 + (y+1)^2 = 169. The point (15,4) is on the circle. Find an equation for the

Top answer: C(3,-1), P(15,4). m1 = (4+1) / (15-3) = 5/12. m2 = -12/5 = Negative reciprocal 0f m1. P(15,4). Y = Read more.
Point P(2,1) and Q(4,-5) lie on a circle. Ifline 2x-y-13=0 is a tangent to the circle at Q, what is (*) Coordinates of the

Top answer: (a) the perpendicular bisector of the chord PQ contains the center of the circle. Since PQ has slope Read more.
A circle of radius 3 is centered at the origin and passes through the point (2,−5‾‾√).(a) Find an equation for the line

Top answer: I expect you meant to say (2,-√5) man, some of the weird notations folks come up with! The line Read more.
Given that the equation of the circle is x^2 + y^2 +2x -8y+5 =0(i)Find the centre and radius of the circle (ii)Determine whether

Top answer: 1. x^2+2x+(2/2)^2+Y^2-8y+(-8/2)^2=-5+1+16. X^2+2x+1 + Y^2-8y+16 = 12. (x+1)^2 + (y-4)^2 = 12. Read more.
Given that the equation of the circle is x^2+y^2+2x-8y+5=0(i)find the centre and radius of the circle (ii)Determine whether the

Top answer: x^2+2x+1 + y^2-8y+16=1+16-5 (x+1)^1 + (y-4)^2=12 center, -1,4 radius sqrt12 Read more.