Question

(2x^(2)+7x-15)/(2x^(2)+13x+15)

Answer 1

I get it to factor to

(x+5)(2x-3)/[(x+5)(2x-3)]

take it from there.

Answer 2

(x+5)(2x-3)/[(x+5)(2x+3)]

Answer 3

[AI-generated answer — Explain Bot]

To simplify the expression (2x^2 + 7x - 15) / (2x^2 + 13x + 15), we can factor both the numerator and denominator and try to cancel out common factors:

First, let's factor the numerator. We can do this by finding two values that multiply to -15 and add up to 7. The values 5 and -3 satisfy this condition, so we can factor the numerator as (2x - 3)(x + 5).

Next, let's factor the denominator. Here, we need to find two values that multiply to 15 and add up to 13. The values 3 and 5 satisfy this condition, so we can factor the denominator as (2x + 3)(x + 5).

Now we can cancel out the common factors in the numerator and denominator, which in this case is (x + 5):

[(2x - 3)(x + 5)] / [(2x + 3)(x + 5)]

Now we are left with:

(2x - 3) / (2x + 3)

And that is the simplified form of the expression (2x^2 + 7x - 15) / (2x^2 + 13x + 15).