Solve the system
4x - 7y = 5
14y = 8x + 10
I got y = 10/-13
x = -5/52
but it doesn't seem right
arrange the second to
8x - 14y = -10
divide by 2
4x - 7y = -5
when you subtract the two you would get
0 = 10 , which of course is nonsense.
So the system has no solution (since both x's and y's dropped out and we ended up with a false statement)
What the "system" was trying to do was finding out where two parallel lines would meet. (they don't)
For 8x - 14 y = 10
wouldn't it be 10 and not -10?
the way I learned it was to solve for x first and then put the equation for x into the second equation to get y.
ok, let's do it your way....
1st:
4x - 7y = 5
4x = 7y + 5
x = (7y+5)/4
into the 2nd:
14y = 8(7y+5)/4 + 10
14y = 2(7y+5)
14y = 14y + 10
0 = 10
same result!!!
As to your first question in this reply ...
14y = 8x + 10
14y - 8x = 10 , multiply by -1
-14y + 8x = -10 or
8x - 14y = -10
thank you!
To solve the given system of equations:
1. Start by isolating one variable in one of the equations. Let's isolate y in the second equation:
14y = 8x + 10
Divide both sides of the equation by 14:
y = (8x + 10)/14
Simplify the equation:
y = (4x + 5)/7
2. Now, substitute the value of y from the second equation into the first equation:
4x - 7((4x + 5)/7) = 5
Simplify the equation:
4x - 4x - 5 = 5
Combine like terms:
-5 = 5
The equation -5 = 5 is false, which means there is no solution to this system of equations. The system is inconsistent, and the equations represent parallel lines that do not intersect.
Therefore, the values you obtained for y = 10/-13 and x = -5/52 are incorrect because they do not satisfy the original system of equations.