1/(sin(x-sinx))?
d/dx [1/(sin(x-sinx))] = -1/[sin^2(x-sin(x)] * d/dx [sin(x-sin(x))] = -cos(x-sin(x))/[sin^2(x-sin(x)]* d/dx [x-sin(x)] = [cos(x)-1]cos(x-sin(x))/[sin^2(x-sin(x)]
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