i really need help on this,and i need an answer quick as possible! ><

what is the probability of picking a white sock and then a brown sock from a sock drawer,if it contains 10 whites,5 browns,and 8 multi-colored socks?

assuming you pick the white, then NOT putting it back in the drawer..

Pr(W,B)=10/23 * 5/22

25/253

2/23 PROBLY

To determine the probability of picking a white sock and then a brown sock, you need to follow these steps:

Step 1: Find the probability of picking a white sock first.
The probability of picking a white sock can be calculated by dividing the number of white socks by the total number of socks in the drawer. In this case, there are 10 white socks and a total of 10 whites + 5 browns + 8 multi-colored socks = 23 socks in the drawer. So, the probability of picking a white sock is 10/23.

Step 2: Find the probability of picking a brown sock next.
Once you have picked a white sock, there will be one less white sock in the drawer, but the total number of socks will remain the same. Now we need to determine the probability of picking a brown sock out of the remaining socks. There are 5 brown socks and 23 - 1 = 22 socks remaining in the drawer. Therefore, the probability of picking a brown sock is 5/22.

Step 3: Multiply the probabilities.
To find the probability of both events happening (picking a white sock and then a brown sock), you need to multiply the probabilities obtained in step 1 and 2. So, the overall probability is (10/23) * (5/22) = 50/506 ≈ 0.099 ≈ 9.9%.

Therefore, the probability of picking a white sock and then a brown sock from the sock drawer is approximately 9.9%.