I need help with 3(x-1)+5=15x +7-4-4(3x+1)+ 3
3(x-1)+5=15x +7-4-4(3x+1)+ 3
3x - 3 + 5 = 15x + 7 - 4 - 12x - 4 + 3
3x - 15x + 12x = 7 - 2 - 8 + 3
0 = 0
3(x - 1) + 5 = 15x+7 -4 -4(3x + 1) +3
3x - 3 + 5 - 15x + 7-4 - 12x -4 +3 =
2 = 2
Is this an Eq ? If so, check it for
errors. Also check the signs.
Jane: this equation is meaningless. For instance:
Solve 3x-x-x-x=5-4-1
0x=0
so x can be any value and the equation is valid. There is No unique solution.
To solve this equation, we need to simplify both sides and combine like terms. Let's break down the steps to solve it:
Step 1: Distribute the multiplication
Start by distributing the multiplication on both sides of the equation.
On the left side: 3(x-1) = 3x - 3
On the right side: -4(3x+1) = -12x - 4
Now the equation becomes:
3x - 3 + 5 = 15x + 7 - 4 - 12x - 4 + 3
Step 2: Combine like terms
Combine the variable terms and the constant terms separately on both sides.
On the left side: 3x - 3 + 5 = 3x + 2
On the right side: 15x + 7 - 4 - 12x - 4 + 3 = 3x -1
Now the equation becomes:
3x + 2 = 3x - 1
Step 3: Isolate the variable
To isolate the variable, we need to move all terms involving x to one side of the equation and the constant terms to the other side.
Subtract 3x from both sides:
3x - 3x + 2 = 3x - 3x - 1
Simplifying, the equation becomes:
2 = -1
Step 4: Analyzing the result
We have arrived at a contradiction because 2 does not equal -1. Therefore, the initial equation does not have a solution.