Consider the experiment of rolling a single die. What is the probability of rolling a number that is divisible by 2 or 3?
A die usually has six faces with 1 to 6 dots. Out of the six numbers, how many of these are divisible by 2 or 3?
2/3
To calculate the probability of rolling a number that is divisible by 2 or 3, we first need to determine the total number of outcomes when rolling a single die.
When rolling a standard six-sided die, there are six possible outcomes: 1, 2, 3, 4, 5, and 6.
Now, let's consider the numbers that are divisible by 2 or 3. Divisible by 2 would be 2, 4, and 6, while divisible by 3 would be 3 and 6. However, since the number 6 is divisible by both 2 and 3, we need to be careful not to count it twice.
So, we have a total of four outcomes that are either divisible by 2 or 3: 2, 3, 4, and 6.
Therefore, the probability of rolling a number that is divisible by 2 or 3 would be 4 (favorable outcomes) divided by 6 (total possible outcomes).
Calculating this, the probability would be 4/6, which can be simplified to 2/3 or approximately 0.667.
So, the probability of rolling a number that is divisible by 2 or 3 is 2/3 or approximately 0.667.