s(x)=1/5x^2
Can anyone help me find the vertex of this equation and the line of symmetry I tried to do it but am finding in difficult. Thanks.
I assume you mean s(x) = (1/5)*x^2, which is a parabola, and not
1/(5*x^2), which has no vertex.
The vertex (minimum value of s) is at (0,0) and the axis of symmetry is s(x) = 0 (the y axis). That is because s(-x) = s(x)