Can someone help me find the y and x intercept, or tell me how to do it please.
f(x)=x^2-5x+4
Set x = 0 and solve for the y intercepts. "y" and f(x) mean the same thing.
Then set f(x)= y = 0 and solve for the x intercepts. There is only one y-intercept, at f(x) = y = +4.
Thank you.
Please tell me if this is correct.
x=4
y=-5
That is neither the x-intercept nor the y-intercept.
I already told you that the y intercept is at x=0, y=4.
The x intercepts are at x = (4,0) and at (1,0)
y=3x+3 and y=-2x+3
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If you are trying to solve two simultaneous equations in two unknowns, subtract the second equation from the first, in this case.
That will leave you with 5x = 0, so x = 0. Use either of the original equations for y.
Sure! Finding the y-intercept and x-intercepts of a function can help provide insights into the behavior and shape of a graph. To find the y-intercept, you need to set x equal to zero and solve for the corresponding value of y. To find the x-intercepts, you need to set y equal to zero and solve for the corresponding values of x.
Let's start by finding the y-intercept of the function f(x) = x^2 - 5x + 4. To find the y-intercept, we set x equal to zero:
f(0) = (0)^2 - 5(0) + 4
f(0) = 4
So the y-intercept is (0, 4).
Next, let's find the x-intercepts of the function. To do this, we set y (or f(x)) equal to zero and solve for x:
0 = x^2 - 5x + 4
To solve this quadratic equation, you can either factor it or use the quadratic formula:
Factoring:
0 = (x - 1)(x - 4)
By setting each factor equal to zero, we find:
x - 1 = 0 -> x = 1
x - 4 = 0 -> x = 4
So the x-intercepts are (1, 0) and (4, 0).
Therefore, the y-intercept is (0, 4) and the x-intercepts are (1, 0) and (4, 0).