x^2-3x=-10
x^2 -3x = 10 has two integer roots, easily obtained by factoring.
(x-5)(x+2) = 0 x = 5 or -2
x^2 -3x =-10 has two complex roots.
x = [3 +/- i*sqrt(31)]/2
Are you sure you copied the problem correctly?
(x-5)(x+2) = 0 x = 5 or -2
x^2 -3x =-10 has two complex roots.
x = [3 +/- i*sqrt(31)]/2
Are you sure you copied the problem correctly?