Q=50-5P. Solve the equation for P
Choose the right one
P=50-Q
P=50+Q
P=10-5Q
P=10-(1/5)Q
P=50-5Q
If you plot P on the horizontal (x) axis, and Q on the vertical (y) axis, then the slope is -(1/5).
q=50-5P
subtract 50
q-50=-5P
divide by -5
-1/5q-50/-5=P
-1/5Q+10=P
so it's the fourth answer.
Thank You, I thought that was but not 100% sure because I get backwards on the positive and negatives, Do you know how I find out the slope of the line or would graph it then?
so it is negative then? -(1/5) Thank You
To solve the equation for P, you need to isolate the variable P on one side of the equation:
Given equation: Q = 50 - 5P
Step 1: Start by moving the constant term (-5P) to the opposite side of the equation.
Q + 5P = 50
Step 2: Now, move the variable Q to the opposite side of the equation.
5P = 50 - Q
Step 3: To isolate P, divide both sides of the equation by 5.
P = (50 - Q) / 5
Therefore, the correct equation is:
P = (50 - Q) / 5