In which of these compounds is the oxidation state of CI the highest?
a) HCIO2
e) HCIO4
Answer is e
Is there a formula to solve this ?
http://www.chemteam.info/Redox/Redox-Rules.html
Yes, there is a general guideline or formula to determine the oxidation state of an element in a compound.
To find the oxidation state of an element, you can follow these steps:
1. Determine the known oxidation states of the other elements in the compound.
2. Assign the known oxidation states to their respective elements.
3. Assign a variable (x) for the oxidation state of the element you want to find.
4. Calculate the sum of the oxidation states of all the elements in the compound.
5. Set the sum of the oxidation states equal to the overall charge of the compound.
6. Solve for the unknown oxidation state.
Now, let's apply this formula to the given compounds "HCIO2" and "HCIO4" to determine which one has the higher oxidation state for the element Cl.
For HCIO2:
Taking the known oxidation states of H and O as +1 and -2 respectively,
The oxidation state of Cl can be represented as x.
So, (+1) + x + (-2) = 0 (since the compound is uncharged)
x - 1 = 0
x = +1
Therefore, in HCIO2, the oxidation state of Cl is +1.
For HCIO4:
Taking the known oxidation states of H and O as +1 and -2 respectively,
Similar to the previous compound, the oxidation state of Cl can be represented as x.
So, (+1) + x + 4(-2) = 0
x - 7 = 0
x = +7
Hence, in HCIO4, the oxidation state of Cl is +7.
Comparing +1 and +7, it is clear that the highest oxidation state for chlorine (Cl) is in HCIO4.
Therefore, the correct answer is e) HCIO4.