How do you set this problem up?
A laser emits at a wavelength 987 nm. all of its output energy is absorbed in a detector that measures a total energy of .52 joules over a period of 52 seconds. how many photons per second are being emitted by the laser?
E= (hc)/lambda.
You know h, c, and lambda (987 x 10^-9 m), so E will be the energy in joules per photon. Use that to calculate # photons per second.
To determine the number of photons per second emitted by the laser, we need to use the relationship between energy and the wavelength of light.
The energy of a single photon is given by the equation:
E = hc/λ
Where:
E is the energy of a single photon,
h is the Planck's constant (6.62607015 x 10^-34 J*s),
c is the speed of light (2.998 x 10^8 m/s),
λ is the wavelength of light.
First, let's convert the wavelength from nm to meters:
987 nm = 987 x 10^-9 m
Next, we can rearrange the equation to solve for the number of photons per second (N):
N = Energy emitted / Energy per photon
Now, we can substitute the values into the equation:
N = (0.52 J) / [(hc) / λ]
N = (0.52 J) / [(6.62607015 x 10^-34 J*s) * (2.998 x 10^8 m/s) / (987 x 10^-9 m)]
N = (0.52 J) / [(6.62607015 x 10^-34 J*s) * (2.998 x 10^8 m/s) * (987 x 10^-9 m)]
Calculating the result will give you the number of photons per second emitted by the laser.