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Chemistry
Chemical Compounds
Acids
What are the sources of sulfuric acid (H2SO4)?
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Consider the reaction of sulfuric acid, H2SO4, with sodium hydroxide, NaOH.
H2SO4(aq) + 2 NaOH(aq) -> 2H2O(l) + Na2SO4(aq).
Top answer:
You have 0.0350 L x 0.175M = about 0.006125 mols H2SO4. It will take 2x that for mols NaOH
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If 26.0 mL of 0.110 M NaOH was needed to neutralize 10.0 mL of an unknown sulfuric acid (H2SO4) solution, what is the
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2NaOH + H2SO4 ==> Na2SO4 + 2H2O millimoles NaOH = mL x M = 26.0 x 0.110 = 2.86 From the equation you
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Given the balanced neutralization equation: H2SO4+2KOH→K2SO4+2H2O
How many moles of potassium hydroxide (KOH) are required to
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right. Go the head of the class.
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Commercially available concentrated sulfuric acid is 18.0 M H2SO4. Calculate the volume (in mL) of concentrated sulfuric acid
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mL x M = mL x M
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Enough concentrated sulfuric acid solution was added to provide 3 grams of sulfuric acid which dissolved i4 grams of pure
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A poorly worded question. What you want to know is how much H2SO4 was used, not how much xs was
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which one of the following statements about sulfuric acid is correct?
A. sulfuric acid is a known muriatic acid B. sulfuric acid
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2018!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!11
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Sulfuric acid (H2SO4) is a very strong diprotic
acid. If 0.036 moles of sulfuric acid is mixed with water to make 576 mililiter
Top answer:
Molarity=(moles/Litersvolume)* 2
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Sulfuric acid (H2SO4) is a very diprotic acid. If 0.046 moles of sulfuric acid is mixed with water to make 638 mililiter of
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M = mols/L of solution.
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Sulfuric acid (H2SO4) is a very strong diprotic
acid. If 0.062 moles of sulfuric acid is mixed with water to make 200 mililiter
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To find the molarity of H+ (hydrogen ions), we need to calculate the amount of H+ ions present in
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Sulfuric acid (H2SO4) is a very strong diprotic
acid. If 0.065 moles of sulfuric acid is mixed with water to make 456 mililiter
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If only one H^+ is involved, you will have 0.065 moles/0.456L = ??M I don't know if you are to
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