how do i get rid of the fractions in this expression ? its supposed to be using order of operations
original problem:
(6^2 + 18) divided by 9 + 2/3(8)-6
To provide help, we must know exactly what the question is.
The given expression can be interpreted in many ways, depending on whether parentheses are missing.
If no parentheses are missing, it is interpreted as:
((6^2 + 18)/9) + ((2/3)*(8)) - 6
Does the interpreted expression represent the question correctly?
Remember that the fractions in text-books are expressed using typography which has to be replaced by properly inserting parentheses. Numerators and denominators containing more than one term have to be enclosed in parentheses.
yes that's represents the question correctly, but how do i get rid of the fractions?
(6^2 + 18) divided by 9 + 2/3(8)-6
= 54/9 + 16/3 - 6
= 6 + 16 - 6
= 16/3 or 5 1/3
http://www.google.com/search?rls=ig&hl=en&source=hp&q=%286%5E2+%2B+18%29%2F9+%2B+2%2F3%288%29-6+&btnG=Google+Search&aq=f&aqi=&aql=&oq=&gs_rfai=
To get rid of the fractions in the expression and solve it using the order of operations, you can follow these steps:
Step 1: Simplify the numerator of the fraction.
In this case, you have 2/3(8). To simplify it, multiply 2/3 by 8. The result is 16/3.
Step 2: Continue simplifying the expression.
Now that you have simplified the fraction, you can rewrite the original expression as:
(6^2 + 18) / 9 + (16/3) - 6.
Step 3: Simplify the exponent.
Evaluate 6^2, which means multiplying 6 by itself.
6^2 = 6 * 6 = 36.
Step 4: Simplify the inside of the parentheses.
Calculate (36 + 18) = 54.
Step 5: Simplify the division.
Divide 54 by 9, which gives 6.
Step 6: Plug in the simplified values.
Now that you have simplified all the parts, the expression becomes:
6 + (16/3) - 6.
Step 7: Combine like terms.
Subtract 6 from 6, which gives 0.
Step 8: Add the fractions.
To combine 16/3 and 0, find a common denominator. In this case, the common denominator is 3, and the expression becomes:
(16/3) + 0 = 16/3.
The final simplified expression is 16/3.