identify the equation of the line through (-2, 1) and parallel to y = 3x + 1
answered in your last post.
Please do not repeat the same question without checking if it has been answered.
That was a different question!
OH ?
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To find the equation of a line parallel to a given line, we need to remember that parallel lines have the same slope.
The given line is in the slope-intercept form, y = mx + b, where m is the slope of the line. From the given equation, we can see that the slope of the given line is 3.
Since the line we are looking for is also parallel, it will have the same slope. So, the slope of the line we are looking for is also 3.
Now that we know the slope (m) of the line we need, we can use the point-slope formula to find the equation. The point-slope formula is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line, and m is the slope.
Given the point (-2, 1) that the line passes through and the slope m = 3, we can substitute these values into the point-slope formula:
y - 1 = 3(x - (-2))
Simplifying, we have:
y - 1 = 3(x + 2)
Now, let's expand the equation:
y - 1 = 3x + 6
To get the equation in the slope-intercept form (y = mx + b), let's isolate y:
y = 3x + 6 + 1
y = 3x + 7
Therefore, the equation of the line through (-2, 1) and parallel to y = 3x + 1 is y = 3x + 7.