one number is 2 more than 3 times another . their sum is 22 . find the number
4,18
fist no. -- x
2nd no. -- 3x+2
3x+2 + x = 22
4x = 20
x = 5
so one is 5, the other 17
Your numbers do not satisfy your condition.
Let's call the first number x and the second number y.
According to the problem, one number is 2 more than 3 times the other. So, we can write the following equation:
x = 3y + 2 (equation 1)
The sum of the two numbers is 22. So, we can write another equation:
x + y = 22 (equation 2)
Now, let's substitute equation 1 into equation 2:
(3y + 2) + y = 22
Simplifying:
4y + 2 = 22
Subtracting 2 from both sides:
4y = 20
Dividing both sides by 4:
y = 5
Now, substitute the value of y into equation 1 to find x:
x = 3y + 2
x = 3(5) + 2
x = 15 + 2
x = 17
So, the two numbers are 17 and 5.
To find the number, we can set up a system of equations based on the given information. Let's denote the first number as "x" and the second number as "y".
From the problem statement, we know that one number is 2 more than 3 times the other. This can be expressed as:
x = 3y + 2 (Equation 1)
Additionally, we are given that the sum of the two numbers is 22:
x + y = 22 (Equation 2)
Now we can solve this system of equations to find the values of x and y.
First, let's solve Equation 1 for x:
x = 3y + 2
Next, substitute this expression for x in Equation 2:
(3y + 2) + y = 22
Simplifying the equation:
4y + 2 = 22
Subtracting 2 from both sides:
4y = 20
Dividing both sides by 4:
y = 5
Now that we have found the value for y, we can substitute it back into Equation 1 to find the value of x:
x = 3y + 2
x = 3(5) + 2
x = 15 + 2
x = 17
So, the two numbers are 17 and 5.