Electronic flash units for cameras contain a capacitor for storing the energy used to produce the flash. In one such unit, the flash lasts for a time interval of 1.49×10−3 with an average light power output of 2.60×105 .
The time interval is illegible
There are no units for light power. Is it watts?
There also seems to be no question.
To calculate the energy stored in the capacitor of the flash unit, we first need to find the total energy output of the flash.
The average power output of the flash is given as 2.60x10^5 watts. Power is defined as the rate at which energy is transferred, so we can multiply the average power by the duration of the flash to find the total energy output.
Energy = Average Power x Duration
Plugging in the given values, we have:
Energy = 2.60x10^5 watts x 1.49x10^-3 seconds
To simplify the calculation, we can convert the units:
1 watt = 1 joule/second
Energy = 2.60x10^5 joules/second x 1.49x10^-3 seconds
Energy = 386.9 joules
So, the total energy output of the flash is 386.9 joules.
Now, since the energy used to produce the flash is stored in the capacitor, we can say the energy stored in the capacitor is also 386.9 joules.