Given 115 grams of Na2SO4 find:
a. the # of moles in sodium sulfate
b. the # of moles in sodium ions
Please explain all work and fully explain where each # came from. Thanks.
2Na + SO4 -> Na2SO4
-first convert the 115 grams of Na2SO4 to moles by dividing by its molar mass
-next use the mole ratio (i.e. the coefficients of the reactants and product)
To find the number of moles in sodium sulfate (Na2SO4) and the number of moles in sodium ions, we need to use the molar mass and stoichiometry of the compound.
a. The molar mass of Na2SO4 can be calculated by adding up the atomic masses of its constituent elements.
Molar mass of Na2SO4 = (2 * atomic mass of Na) + atomic mass of S + (4 * atomic mass of O)
The atomic mass of Na is 22.99 g/mol, the atomic mass of S is 32.07 g/mol, and the atomic mass of O is 16.00 g/mol.
Molar mass of Na2SO4 = (2 * 22.99) + 32.07 + (4 * 16.00) = 114.98 g/mol
To find the number of moles, we can divide the given mass by the molar mass:
Number of moles of Na2SO4 = Mass of Na2SO4 / Molar mass of Na2SO4
= 115 g / 114.98 g/mol
≈ 1.000 mol (rounded to three decimal places)
Therefore, there are approximately 1.000 moles of Na2SO4 in 115 grams of the compound.
b. In Na2SO4, there are two sodium (Na) ions. To find the number of moles of sodium ions, we can use stoichiometry.
The ratio of sodium ions (Na+) to Na2SO4 is 2:1. This means that for every 2 moles of Na2SO4, there are 2 moles of sodium ions.
Number of moles of Na+ = (Number of moles of Na2SO4) * (2 moles of Na+ / 1 mole of Na2SO4)
= 1.000 mol * (2/1)
= 2.000 mol
Therefore, there are 2.000 moles of sodium ions in 115 grams of Na2SO4.