5(4r-3c)-2(7r-9c)=0 solve for r
This is all I know how to do and don't know if it's even right. Or what to do from here.
5(4r-3c)-2(7r-9c)=0 solve for r
20r-15c-14r-11c=0
6r-26c=0
see the post above this, follow the same steps
this is the steps:
20r-15c-14r+18c=0
6r+3c=0
so for my final answer I got r=c/2 is that correct?
close ...
from your second last line
6r + 3c = 0
6r = - 3c
r = -c/2
btw, I am glad you caught your error in the steps of your original at the top,
where did the -11c come from?
To solve for r in the equation 5(4r-3c)-2(7r-9c)=0, we need to simplify the equation and isolate the term with r.
First, distribute the multiplication on both sides of the equation:
20r - 15c - 14r + 18c = 0
Combine like terms:
(20r - 14r) + (-15c + 18c) = 0
6r + 3c = 0
Now, isolate the term with r by subtracting 3c from both sides of the equation:
6r = -3c
Finally, solve for r by dividing both sides of the equation by 6:
r = -3c/6
Therefore, the solution for r is equal to -3c/6.