1. If the first and third of three consecutive odd integers are added, the result is 51 less than five times the second integer. Find the third integer.
2. Write as a subtraction problem and evaluate.
15 less than -2
n, n+1, N+2, ... are consecutive intergers.
N, N+2, N+4, ... are consecutive odd integers.
15 less than -2
-2-15=. Check my thinking
1. To find the third integer in a sequence of consecutive odd integers, we need to set up an equation based on the given information.
Let's assume the first odd integer is "N". The second odd integer would be "N + 2" since they are consecutive. And the third odd integer would be "N + 4".
According to the problem, the sum of the first and third odd integers is 51 less than five times the second odd integer:
(N) + (N + 4) = 5(N + 2) - 51
Simplifying this equation:
2N + 4 = 5N + 10 - 51
2N - 5N = 10 - 51 - 4
-3N = -45
N = -45 / -3
N = 15
So the first odd integer in the sequence is 15. To find the third integer, we substitute the value of N back into the equation:
N + 4 = 15 + 4 = 19
Therefore, the third odd integer is 19.
2. To write 15 less than -2 as a subtraction problem, we can rewrite it as -2 - 15.
To evaluate this expression, we simply subtract 15 from -2:
-2 - 15 = -17
So 15 less than -2 is equal to -17.