I need help with this problem.
(b+7)(b+1) .
Use FOIL
First: b^2
Outer: 1b
inner:7b
last: 7
b^2+8b+7
R - 8=2
B squared plus eight
To solve the problem, you need to use the distributive property, which states that when you multiply a sum by a number, you can multiply each term in the sum separately and then add the results. Here's how you can apply the distributive property to the given expression:
1. Multiply the first terms of each binomial: (b+7)(b) = b * b = b^2.
2. Multiply the outer terms of each binomial: (b+7)(1) = b * 1 = b.
3. Multiply the inner terms of each binomial: (7)(b) = 7 * b = 7b.
4. Multiply the last terms of each binomial: (7)(1) = 7 * 1 = 7.
5. Simplify the equation by combining like terms:
b^2 + b + 7b + 7 = b^2 + 8b + 7.
Therefore, the result of the expression (b+7)(b+1) is b^2 + 8b + 7.