If BC=2, AB=2 and B'C'=4 then compute A'B'
the picture is a box starting lower left, the letters go A',B',C',P' clockwise. Then there are lines that go down to form a tip. In the middle going down those lines its just A,B,C,P. Then where it meets at the point it is A",B",C",P". I tried tinyurl but it wont let me upload the picture!
To compute A'B', we need to find the length of the line segment A'B'.
From the given information, we know that BC = 2, AB = 2, and B'C' = 4.
First, let's calculate the length of line segment AC using the Pythagorean theorem. AC represents the base of the triangle ABC.
AC^2 = AB^2 + BC^2
AC^2 = 2^2 + 2^2
AC^2 = 4 + 4
AC^2 = 8
Taking the square root of both sides:
AC = √8
Now, let's compute the length of line segment A'C', which represents the base of triangle A'B'C'.
A'C' = AC + B'C'
A'C' = √8 + 4
Finally, we can find the length of A'B' using the equation:
A'B' = A'C' + B'C'
A'B' = (√8 + 4) + 4
To simplify the expression further, you can calculate the square root of 8 and then add the numbers together to find the final value of A'B'.