Physics  Range of projectile motion
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We consider a projectile motion against a linear drag force D = −b∗v, where v is the velocity of the projectile. (A) Suppose only a vertical drop (in zdirection), v = vz, from an initial height H with an initial velocity voz
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So my question is about projectile motion. We just learned in class about the equation for finding the range: R=v^2sin(2theta)/g I understand that and I think I see where it comes from. My question is, if someone were to collect
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I don't understand. derive a general equation that will predict the horizontal range of a projectile that is fired from one vertical position and ends at any other vertical position with an initial velocity, V1, at an angle,
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I don't understand. derive a general equation that will predict the horizontal range of a projectile that is fired from one vertical position and ends at any other vertical position with an initial velocity, V1, at an angle,
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Q Exactly 2.7s after a projectile is fired into the air from the ground ,it is observed to have a velocity v = (8.8i+4.5 j) m/s where the xaxis is horizontal and the y axis is positive upward . a)Determine the horizontal range of
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The range R of a projectile is defined as the magnitude of the horizontal displacement of the projectile when it returns to its original altitude. (In other words, the range is the distance between the launch point and the impact
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i don't understand the projectile motion...my teacher said...it's a motion of a body confined to a vertical plane, perpendicular to Earth's surface... I don't get it, can anyone explain to me clearly???? plzzzzz....THX!!!! If your
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