if BC=2, AB=2 and B'C'=4 then compute A'B'

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how do i put the figure on this site? i can't cut and paste it

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Figure is a square. from bottom left clockwise goes A' B' C' P' at each point then diagonal lines going to tip under square until all points touch. second line in head down is just A,B,C and P then bottom where the lines connect is A" B" C" P"

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I do not understand your verbal description of the figure, especially "tip under the square" and "second line in head down"

If BC=2, AB=2 and B'C'=4 then compute A'B'

the picture is a box starting lower left, the letters go A',B',C',P' clockwise. Then there are lines that go down to form a tip. In the middle going down those lines its just A,B,C,P. Then where it meets at the point it is A",B",C",P". I tried tinyurl but it wont let me upload the picture!

To compute A'B', we can use the concept of similar triangles. We know that BC = 2, AB = 2, and B'C' = 4.

First, let's draw a diagram to visualize the situation:

```
A --------- B
\ /
\ /
C

C' ------- B'
```

In triangle ABC, we have BC = 2 and AB = 2. Since BC = AB, triangle ABC is an isosceles triangle.

Now, let's consider the ratios between the corresponding sides of triangles ABC and A'B'C'. From the given information, we can deduce that BC/B'C' = AB/A'B'.

Substituting the known values, we have:

2/4 = 2/A'B'

To solve for A'B', we can cross-multiply and solve the equation:

2 * A'B' = 4 * 2

2 * A'B' = 8

Dividing both sides by 2:

A'B' = 8/2

A'B' = 4

Therefore, A'B' is equal to 4.