# radical equation - no solution right?

radical sign (w + 5) = 2

In all my problems there are a letter variable on the end

example:

radical sign (-u + 30) = u

I then square both sides, drop the radical sign then
(u+6)(u-5)=0
then check to see if they are both true

I guess my question is this is a no solution problem right?

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1. sqrt (36)=-6 checks, so u=-6 is ok
sqrt (25)=5 is ok

Both are solutions. I am wondering why you thought no solution.

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bobpursley

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