a robot drops a camera off the rim of a 239 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s
and the question is....
To find the time it takes for the camera to reach the ground, we can use the equation of motion for free-fall:
\[ h = \frac{1}{2}gt^2 \]
Where:
- h is the height of the cliff (239 m)
- g is the acceleration due to gravity on Mars (3.7 m/s²)
- t is the time it takes for the camera to fall
First, let's rearrange the equation to solve for time (t):
\[ 2h = gt^2 \]
\[ t^2 = \frac{2h}{g} \]
\[ t = \sqrt{\frac{2h}{g}} \]
Now, substitute the given values:
\[ t = \sqrt{\frac{2 \times 239}{3.7}} \]
\[ t \approx 12.87 \ \text{s} \]
Therefore, it would take approximately 12.87 seconds for the camera to reach the ground on Mars.