Two airplanes start at the same time and fly
toward each other from points 1000 km apart at rates of
420 km/h and 330 km/m . After how many hours will
they meet?
The distance between them decreases at a rate 750 km/h. The time requires for them to meet is 1000/750 = 4/3 hours of 1 hour and 20 minutes.
To find out after how many hours the two airplanes will meet, we need to use the formula:
Distance = Rate × Time
Let's assume that the time it takes for them to meet is "t" hours.
The first airplane is traveling at a rate of 420 km/h, so the distance it covers in "t" hours is 420t km.
Similarly, the second airplane is traveling at a rate of 330 km/h, so the distance it covers in "t" hours is 330t km.
Since they are flying towards each other, the sum of the distances covered by the two airplanes should be equal to the total distance they need to meet, which is 1000 km.
Therefore, we can write the equation:
420t + 330t = 1000
Combine the like terms:
750t = 1000
Divide both sides of the equation by 750:
t = 1000 / 750
t = 1.33 hours
Therefore, the two airplanes will meet after approximately 1.33 hours.