If a pro basketball player has a vertical leap of 25 inches, what is his hang time? Use the hang time function V = T^2
Hang time is _________ seconds. Simplify the answer. Type an integer or a decimal Round to the nearest tenth.
The answer I came up with is .52 seconds. Can anyone verify that I am right or wrong?
If V = T^2, assuming V = vertical leap and T= time
25 = T^2
5 = T
To find the hang time, we can use the hang time formula V = T^2, where V represents the vertical leap and T represents the hang time.
In this case, we are given that the pro basketball player has a vertical leap of 25 inches. We want to find the hang time, so we can rearrange the formula to solve for T.
V = T^2
T = √V
Substituting the given value of V into the formula, we get:
T = √25
T = 5
Therefore, the hang time of the basketball player is 5 seconds, not 0.52 seconds as you have mentioned.