What mass of chloral hydrate (C2H3Cl3O2) would contain 1.0 grams of chlorine?
Do you want 1 g Cl2 or 1 g of the Cl atom?
I expect you want 1 g chlorine atom (not Cl2).
moles Cl = 1/atomic mass Cl = 1/35.5 = 0.0282 moles Cl.
Since chloral hydrate contains 3 Cl atoms/mole of the hydrate you will want 1/3 x (0.0282) = ?? moles hydrate.
g hydrate = moles hydrate x molar mass hydrate.
If I have interpreted the problem the wrong way, just adjust the numbers above to fit.
Well, let me calculate that for you while trying not to chloroform you with a bad joke. The molar mass of chloral hydrate is 165.39 g/mol. And since there are 3 chlorine atoms in one molecule of chloral hydrate, the molar mass of chlorine is 35.45 g/mol.
To find the mass of chloral hydrate that would contain 1.0 gram of chlorine, we set up a proportion:
1.0 g Cl / 35.45 g/mol Cl = x g CH / 165.39 g/mol CH
Cross-multiplying and solving for x, we get:
x = (1.0 g Cl * 165.39 g/mol CH) / 35.45 g/mol Cl
x ≈ 4.68 g
So, approximately 4.68 grams of chloral hydrate would contain 1.0 gram of chlorine. If you need any more chemical humor, don't hesitate to ask!
To determine the mass of chloral hydrate (C2H3Cl3O2) that contains 1.0 gram of chlorine, we need to find the molar mass of chlorine and chloral hydrate.
The molar mass of chlorine (Cl) is approximately 35.45 g/mol.
The molar mass of chloral hydrate (C2H3Cl3O2) can be calculated by adding up the atomic masses of each element:
C: 2 atoms x 12.01 g/mol = 24.02 g/mol
H: 3 atoms x 1.01 g/mol = 3.03 g/mol
Cl: 3 atoms x 35.45 g/mol = 106.35 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol
Total molar mass of chloral hydrate (C2H3Cl3O2):
24.02 g/mol + 3.03 g/mol + 106.35 g/mol + 32.00 g/mol = 165.40 g/mol
To find the mass of chloral hydrate containing 1.0 gram of chlorine, we can use the following proportion:
(1.0 g Cl) / (35.45 g/mol Cl) = (x g chloral hydrate) / (165.40 g/mol chloral hydrate)
Cross-multiplying and solving for x, we have:
x g chloral hydrate = (1.0 g Cl) * (165.40 g/mol chloral hydrate) / (35.45 g/mol Cl)
x g chloral hydrate = 4.69 g
Therefore, approximately 4.69 grams of chloral hydrate would contain 1.0 gram of chlorine.
To find the mass of chloral hydrate (C2H3Cl3O2) that contains 1.0 gram of chlorine, we need to determine the molar mass of chloral hydrate and then calculate the mass using stoichiometry.
1. First, calculate the molar mass of chloral hydrate (C2H3Cl3O2):
- The molar mass of carbon (C) is 12.01 g/mol.
- The molar mass of hydrogen (H) is 1.01 g/mol.
- The molar mass of chlorine (Cl) is 35.45 g/mol.
- The molar mass of oxygen (O) is 16.00 g/mol.
So the molar mass of chloral hydrate can be calculated as follows:
Molar mass = (2 * molar mass of carbon) + (3 * molar mass of hydrogen) + (3 * molar mass of chlorine) + (2 * molar mass of oxygen)
= (2 * 12.01 g/mol) + (3 * 1.01 g/mol) + (3 * 35.45 g/mol) + (2 * 16.00 g/mol)
= 165.38 g/mol
Therefore, the molar mass of chloral hydrate is 165.38 g/mol.
2. Next, use stoichiometry to calculate the mass of chloral hydrate containing 1.0 gram of chlorine:
Since there are 3 chlorine atoms in one mole of chloral hydrate (C2H3Cl3O2), we can set up the following ratio:
(1 mol chloral hydrate) / (3 mol chlorine) = (mass of chloral hydrate) / (1.0 g chlorine)
Rearranging the equation to solve for the mass of chloral hydrate:
mass of chloral hydrate = (1.0 g chlorine) * [(1 mol chloral hydrate) / (3 mol chlorine)] * (molar mass of chloral hydrate)
Substituting the known values:
mass of chloral hydrate = (1.0 g) * (1 mol / 3 mol) * (165.38 g/mol)
= 55.13 g
Therefore, 55.13 grams of chloral hydrate would contain 1.0 gram of chlorine.