how many moles of LiF would be required to produce a 2.5 M solution with volume of 1.5 M?
Reread and retype your question more carefully. 1.5 M is not a volume.
To determine the number of moles of LiF required to produce a 2.5 M solution with a volume of 1.5 M, we can use the equation:
Molarity (M) = Moles (mol) / Volume (L)
First, let's rearrange the equation to solve for moles:
Moles (mol) = Molarity (M) x Volume (L)
Given:
Molarity = 2.5 M
Volume = 1.5 L
Substituting the given values into the equation:
Moles (mol) = 2.5 M x 1.5 L
Moles (mol) = 3.75 mol
Therefore, 3.75 moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5 L.