p(0)=1atm,p(33) = 2 and so on find the pressure at 180 feet
I put in the wrong number the pressure is 140
i'm not sure about this (if it requires some formulas), but i used extrapolation:
X Y
0 1
33 2
140 y
therefore,
(y-1)/(y-2)=(140-0)/(140-33)
y=5.24
so there,, =)
To find the pressure at 180 feet, we need to determine the pattern or relationship between the depth and the pressure.
In general, as depth increases, the pressure also increases due to the weight of the overlying fluid. This relationship is described by the hydrostatic pressure equation, which states that the pressure at a given depth is equal to the pressure at a reference depth plus the product of the density of the fluid, the acceleration due to gravity, and the difference in depth.
The equation can be written as:
P2 = P1 + (ρ * g * d)
where:
P2 is the pressure at the second depth
P1 is the pressure at the first depth (reference pressure)
ρ is the density of the fluid
g is the acceleration due to gravity
d is the change in depth
Given that the pressure at 0 feet (P1) is 1 atm, and the pressure at 33 feet (P2) is 2 atm, we can use these values to find the density (ρ) and acceleration due to gravity (g).
Since pressure is usually measured in terms of pascals (Pa), we need to convert 1 atm and 2 atm to pascals. 1 atm is approximately equal to 101,325 Pa, and 2 atm is approximately equal to 202,650 Pa.
Now, we can plug the values into the equation:
P2 = P1 + (ρ * g * d)
202,650 Pa = 101,325 Pa + (ρ * g * 33 ft)
Rearranging the equation to solve for ρ * g:
ρ * g = (202,650 Pa - 101,325 Pa) / 33 ft
ρ * g = 101,325 Pa / 33 ft
To get the density (ρ) and acceleration due to gravity (g), we need additional information such as the specific fluid being considered (e.g., water, oil, etc.) and the acceleration due to gravity at the specific location (approximately 9.8 m/s^2 on Earth).
Once we have the density and acceleration due to gravity, we can plug them into the equation to find the pressure at 180 feet:
P2 (180 ft) = P1 (0 ft) + (ρ * g * 180 ft)
Note: It's important to double-check the units used and make any necessary conversions to ensure the equation is consistent with the units being used.