At what rate would a 75kg person travel during a slip/fall on a wet surface to the landing position? And what would be the force of the fall?
More info is needed for an accurate answer.
What matters is the person's height and weight distribution. A 75 kg person will have height about 1.8 m with a center of mass at H = 0.9 m.
The speed when he or she hits the ground will be about sqrt(2gH)= 4 m/s
The force of the fall will depend upon the type of clothing worn. Clothes exert a "cushioning" effect.
An approximate impact IMPULSE could be calculated from momentum principles.
Person is 5'3-1/4." Light clothing, no cushioning effect.
thanks!
Please answer.
For impulse, use mass*approximatevelocity
can you answer the whole question for me?
No
To determine the rate at which a person would travel during a slip/fall on a wet surface, we need to consider the acceleration due to gravity and the distance over which the person falls. Additionally, to calculate the force of the fall, we need to account for the person's mass and the acceleration due to gravity.
1. Rate of travel (velocity):
The rate at which the person would travel can be determined using the laws of motion. Specifically, we can use the equation of motion for falling objects:
v = √(2gh)
where:
- v is the final velocity (rate of travel)
- g is the acceleration due to gravity (approximately 9.8 m/s²)
- h is the height or distance the person falls
To determine the height of the fall, we need more information about the scenario. Let's assume a height of 1 meter for this example. Plugging in the values, we get:
v = √(2 * 9.8 * 1) ≈ 6.26 m/s
Therefore, the rate at which the person would travel during the slip/fall on a wet surface to the landing position is approximately 6.26 meters per second.
2. Force of the fall:
The force of the fall can be calculated using Newton's second law of motion, which states that force (F) is equal to the product of mass (m) and acceleration (a):
F = m * a
In this case, the mass (m) of the person is given as 75 kg, and the acceleration (a) is the acceleration due to gravity (9.8 m/s²). Plugging in the values, we get:
F = 75 kg * 9.8 m/s² ≈ 735 N
Therefore, the force of the fall on a 75kg person would be approximately 735 Newtons.