(d+8/d-9)divided by 9d+72/c-7
Can anyone point me in the right direction to solving this problem? Thank you
Your nonuse of grouping symbols is annoying.
I think you meant this:
(d+8)/(d-9) divided by (9d+72)/(c-7)
well, multiplication is reciprocal of division, so your problem becomes
(d+8)/(d-9) multiplied by (c-7)/(9d-72)
or
(d+8)(9d-72)/((d-9)(c-7) or
9(d+8)(d-9)/((d-9)(c-7)) or
9(d+8)/(c-7)
Thank you for your help sir.
To simplify the given expression ((d+8)/(d-9)) divided by ((9d+72)/(c-7)), we need to follow these steps:
1. Simplify each individual fraction within the expression.
For the numerator ((d+8)/(d-9)), we can't simplify it any further since both the numerator and denominator are already in their simplest form.
For the denominator ((9d+72)/(c-7)), we can factor out a common factor of 9 from both terms:
((9d+72)/(c-7)) = (9(d+8))/(c-7).
2. Invert the denominator fraction and convert the division to multiplication.
To divide fractions, we multiply by the reciprocal of the second fraction. So, we rewrite the expression as: ((d+8)/(d-9)) * ((c-7)/(9(d+8))).
3. Cancel out common factors, if possible.
In this case, (d+8)/(d+8) can be canceled out, simplifying the expression further.
The final simplified expression is: (c-7)/(d-9).