I am having some trouble figuring out these two problems.

1. Calculate the mean, median, mode, range, and midrange for the data set given {-1, 7, 0, 14, -2, -15, 0, 8, 7}
Mean=2
Median=7
Mode=0, and 7
Range=
Midrange=

2. Calculate the mean, range, variance, standard deviation, interquartile range for the data set given {-1, 0, 1, 0, -1, 0, 1, 0, -1, 0, 1, 0}
Mean=0
Range=
Variance=
Standard deviation=
Interquartile range=

I'm not sure with some of them but to find the range take the highest number (maximum) and subtract the lowest number (minimum).

To calculate the missing values in both problem 1 and problem 2, we can follow these steps:

Problem 1:
1. Mean: The mean is calculated by summing up all the values in the dataset and dividing it by the number of values present. For the given dataset {-1, 7, 0, 14, -2, -15, 0, 8, 7}, the mean is found by adding all the values together and dividing by 9. Thus, the mean is 2.
2. Median: The median is the middle value in a sorted dataset. First, sort the dataset in ascending order {-15, -2, -1, 0, 0, 7, 7, 8, 14}. Since there are 9 values, the median would be the (9+1)/2 = 5th value, which is 7.
3. Mode: The mode is the most frequently occurring value(s) in a dataset. In this case, both 0 and 7 occur more than once, so the mode is 0 and 7.
4. Range: The range is the difference between the highest and lowest values in a dataset. In this case, the highest value is 14, and the lowest value is -15. Therefore, the range is 14 - (-15) = 29.
5. Midrange: The midrange is the average of the highest and lowest values in a dataset. In this case, the midrange is (14 + (-15))/2 = -0.5.

Problem 2:
1. Mean: The mean is calculated by summing up all the values in the dataset and dividing it by the number of values present. For the given dataset {-1, 0, 1, 0, -1, 0, 1, 0, -1, 0, 1, 0}, the mean is found by adding all the values together and dividing by 12. Thus, the mean is 0.
2. Range: The range is the difference between the highest and lowest values in a dataset. In this case, the highest value is 1, and the lowest value is -1. Therefore, the range is 1 - (-1) = 2.
3. Variance: Variance measures how spread out the values are from the mean. To calculate the variance, subtract the mean from each value, square the result, sum up all the squared values, and then divide by the number of values. For this dataset, the variance is calculated as follows: [(-1 - 0)^2 + (0 - 0)^2 + (1 - 0)^2 + (0 - 0)^2 + (-1 - 0)^2 + (0 - 0)^2 + (1 - 0)^2 + (0 - 0)^2 + (-1 - 0)^2 + (0 - 0)^2 + (1 - 0)^2 + (0 - 0)^2] / 12 = 1/3.
4. Standard deviation: The standard deviation is the square root of the variance. Taking the square root of the variance found in the previous step, we get the standard deviation as sqrt(1/3) ≈ 0.577.
5. Interquartile range: The interquartile range is the range between the first quartile (Q1) and the third quartile (Q3) of a dataset. First, sort the dataset in ascending order {-1, -1, -1, 0, 0, 0, 0, 0, 1, 1, 1, 1}. There are 12 values, so Q1 would be the (12+1)/4 = 3.25th value, which falls between 0 and the first 1. Q3 would be the (12+1)*3/4 = 9.75th value, which falls between the second 1 and 1. Therefore, the interquartile range is 1 - 0 = 1.

Note: For the missing values, you need to complete the calculations based on the explanations provided above.