I am working on Factoring the Trinomial and need help to solve this equation: t=3t^3+22t^2+8t
t = 3t^3 + 22t^2 + 8t
subtract t from both sides
3t^3 + 22t^2 + 7t = 0
t is common to each term
t(3t^2 + 22t + 7) = 0
So, t = 0 is one solution.
Factor 3t^2 + 22t + 7 to get the other two solutions.