If you start with ten grams of lithium hydroxide, how many grams of lithium bromide will be produced? Round to the nearest tenth. Don't forget the units.LiOH+HBr--->LiBr+H2O
To determine the mass of lithium bromide produced from ten grams of lithium hydroxide, we need to consider the balanced chemical equation and the molar ratios of the reactants and products.
The balanced chemical equation for the reaction is:
LiOH + HBr → LiBr + H2O
According to the equation, the molar ratio between lithium hydroxide (LiOH) and lithium bromide (LiBr) is 1:1. This means that for every 1 mole of LiOH, 1 mole of LiBr is produced.
To begin, we need to convert the given mass of lithium hydroxide (10 grams) into moles. To do this, we need the molar mass of LiOH:
- Lithium (Li) has a molar mass of approximately 6.94 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.
- Hydrogen (H) has a molar mass of approximately 1.01 g/mol.
Adding these up, we get:
6.94 g/mol (Li) + 16.00 g/mol (O) + 1.01 g/mol (H) = 23.95 g/mol (LiOH)
Now, we can calculate the number of moles of LiOH:
10 g (LiOH) / 23.95 g/mol (LiOH) = 0.418 mol (LiOH) (rounded to three decimal places)
Since the molar ratio between LiOH and LiBr is 1:1, based on the balanced chemical equation, the number of moles of LiBr produced will also be 0.418 mol.
Finally, we can convert the moles of LiBr back into grams. The molar mass of LiBr is approximately 86.85 g/mol (6.94 g/mol + 79.90 g/mol):
0.418 mol (LiBr) × 86.85 g/mol (LiBr) = 36.26 g (LiBr) (rounded to two decimal places)
Therefore, starting with ten grams of lithium hydroxide, approximately 36.3 grams of lithium bromide would be produced.