I need to isolate the mass (m) of Zn in this formula but i am unabable to do so...
0.000595mol= 3(0,0233g - mZn) / 2 (26,98 g/mol) + m Zn / 65.39 g/mol
Please help ASAP!! Thx!
To isolate the mass (m) of Zn in the given formula, we can use algebraic manipulations to rearrange the equation. Here are the steps to solve it:
1. Start with the given equation: 0.000595 mol = 3(0.0233 g - mZn) / 2 (26.98 g/mol) + mZn/65.39 g/mol.
2. First, simplify the right-hand side of the equation within the parentheses: 3(0.0233 g - mZn) / 2 (26.98 g/mol) becomes (0.0699 g - 3mZn) / (53.96 g/mol).
3. Multiply both sides of the equation by the denominator (53.96 g/mol) to eliminate the fraction: (53.96 g/mol) * 0.000595 mol = 0.0699 g - 3mZn.
4. Simplify the left-hand side of the equation: 0.0321732 g = 0.0699 g - 3mZn.
5. Rearrange the equation to isolate the term with the unknown mass (mZn): 3mZn = 0.0699 g - 0.0321732 g.
6. Combine like terms on the right-hand side: 3mZn = 0.0377268 g.
7. Divide both sides of the equation by 3 to solve for mZn: mZn = 0.0377268 g / 3.
8. Calculate the value of mZn: mZn ≈ 0.0125756 g.
Therefore, the mass of Zn (mZn) is approximately 0.0125756 grams.