calculus

find the equation of the tangent line at the given value of x on the curve

2xy-2x+y=-14, x=2

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  1. 2xy-2x+y=-14, x=2

    We want dy/dx
    2xdy/dx + 2xdx/dx - 2dx/dx + dy/dx = 0
    dx/dx = 1
    (2x+1)dy/dx + 2x - 2 = 0

    dy/dx = -2(x-1)/(2x+1)

    now put in x = 2

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    posted by Damon

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