(x^2 + x) + �ã(x^2 + x) - 2 = 0
Is this supposed to say ...
(x^2+x) + √(x^2+x) - 2 = 0 ?
if so, then let y = √(x^2+x)
your equation becomes
y^2 + y - 2 = 0
(y+2)(y-1) = 0
y = -2 or y = 1
sub back into the substitution and you have two quadratic equations to solve.
e.g
√(x^2 + x) = -2 which of course cannot have a real number solution and
√(x^2+x) = 1
square both sides and proceed from there.
A line passes through the points whose coordinates are (c,3c) and (2c,5c).Assuming that c is not 0 find the slope of the line
To solve the given equation (x^2 + x) + �ã(x^2 + x) - 2 = 0, we will combine like terms and simplify the expression.
Step 1: Combine like terms
We have (x^2 + x) + �ã(x^2 + x) - 2 = 0. The terms x^2 + x and �ã(x^2 + x) are like terms.
x^2 + x + �ã(x^2 + x) - 2 = 0
Step 2: Distribute the �ã to the terms inside the parentheses
The √ symbol represents the square root. So, �ã(x^2 + x) means the square root of (x^2 + x).
x^2 + x + √(x^2 + x)^2 - √(x^2 + x)·2 = 0
Step 3: Simplify the expression inside the square root
(x^2 + x)^2 means (x^2 + x) squared, which is equal to (x^2 + x)(x^2 + x).
(x^2 + x + √(x^2 + x)(x^2 + x) - √(x^2 + x)·2 = 0
Step 4: Rewrite the expression
(x^2 + x + √(x^2 + x)(x^2 + x) - 2√(x^2 + x) = 0
Now the equation is simplified. To solve the equation further, we need to set it equal to zero and solve for x. However, it seems there is some mistake or missing information in the original equation. Please double-check and provide the correct equation if needed.