# Chemistry

If 20ml of glacial acetic acid (pure HC2H3O2) is diluted to 1.5L with water, what is the pH of the resulting solution. The density of glacial acetic acid is 1.08g/ml

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1. Call acetic acid HAc.
Calculate M concd HAc.
1.08 g/mL x 1000 mL x (1 mol/molar mass HAc) = ??M HAc.

For the diluted solution,
M HAc x (20 mL/1,500 mL) = ?? M

HAc ==> H^+ + Ac^-
Ka = (H^+)Ac^-)/(HAc)
Set up an ICE chart, substitute into the Ka expression, and solve for H^+, then convert to pH.

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posted by DrBob222

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