Square 1 has an area of 49 sq. in. if each sideof square 2 is 3 times as long as each side of square 1 then waht id the perimeter of square 2
A = s^2
49 = s^2
7 = s
7 * 3 = 21
P = 4s
P = 4 * 21
P = ?
the perimeter would be 84 since 21+21+21+21= 84
hope that helped
To find the perimeter of square 2, we need to determine the length of each side of square 2.
Given that each side of square 2 is 3 times as long as each side of square 1, we can calculate the length of each side of square 1 by taking the square root of its area.
The area of square 1 is given as 49 sq. in., so taking the square root, we find that each side of square 1 is 7 inches long.
Since each side of square 2 is 3 times as long as each side of square 1, each side of square 2 is 3 * 7 inches = 21 inches.
Now we can calculate the perimeter of square 2 by multiplying the length of one side by 4 (since a square has 4 equal sides).
The perimeter of square 2 is: 21 inches (length of one side) * 4 (number of sides of a square) = 84 inches.
Therefore, the perimeter of square 2 is 84 inches.