If log 2 = .3010 log 3 = .4771, find the numerical value of x in 3x+2 = 405

Your first "if" statement is a mathematcial impossibility.

To solve 3x + 2 = 405, just use algebra.
x = 403/3

thz man i just don't understand this stuff...

Check your typing of the question.

There had to be an exponent somewhere in "find the numerical value of x in 3x+2 = 405", otherwise there would have been no need to give you the log of 2 and 3

If log 2 = .3010 log 3 = .4771, find the numerical value of x in 3^x+2 = 405

To find the numerical value of x in the equation 3x + 2 = 405, we need to isolate x on one side of the equation.

First, let's subtract 2 from both sides of the equation to get:
3x = 405 - 2
3x = 403

Now, we can divide both sides of the equation by 3 to solve for x:
x = 403 / 3
x ≈ 134.33

Therefore, the numerical value of x in the equation 3x + 2 = 405 is approximately 134.33.