A flower pot falls off a window ledge 10.0 m above the ground. Its velocity as it hits the ground is?
V = sqrt (2 g H), where H is the height that is falls from, and g is the acceleration of gravity
1.4
To find the velocity of the flower pot as it hits the ground, we can use the principles of physics, specifically the equation for free fall motion.
In this case, the flower pot falls from a height of 10.0 m above the ground.
The equation for the final velocity in free fall is given by:
v^2 = u^2 + 2as
Where:
- v is the final velocity
- u is the initial velocity (which is 0 because the flower pot is initially at rest)
- a is the acceleration due to gravity (approximately 9.8 m/s^2)
- s is the distance fallen (in this case, 10.0 m)
Plugging the values into the equation, we have:
v^2 = 0^2 + 2 * (-9.8 m/s^2) * 10.0 m
Simplifying:
v^2 = 0 + (-196 m^2/s^2)
Since the initial velocity is zero, we can ignore it, and we have:
v^2 = -196 m^2/s^2
To find the velocity, we take the square root of both sides of the equation:
v = √(-196 m^2/s^2)
However, the square root of a negative number is not a real number because it would involve imaginary numbers. In this case, it means there is an error in the problem statement or an issue with the calculation.
Typically, the velocity would be positive when the object hits the ground. Therefore, in a normal scenario, when the flower pot falls and there are no external factors involved, the velocity would be approximately 14 m/s as it hits the ground.