The Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than .4 ounces. Suppose that 800 jawbreakers are selected at random from the production lines. Would it be unusual for this sample of 800 to contain 418 jawbreakers that weigh more than .4 ounces?
To determine whether it would be unusual for a sample of 800 jawbreakers to contain 418 that weigh more than 0.4 ounces, we need to compare it to the expected outcome based on the stated claim by Acme Candy Company.
Step 1: Calculate the expected number of jawbreakers that weigh more than 0.4 ounces based on the claim.
Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than 0.4 ounces. So, the expected proportion of jawbreakers weighing more than 0.4 ounces is 0.60.
Expected number = (Expected proportion) * (Total sample size)
Expected number = 0.60 * 800 = 480
Step 2: Determine if the observed value is unusual based on the expected value.
To determine if 418 jawbreakers weighing more than 0.4 ounces is unusual, we need to compare it to the expected value of 480.
Since the company claims that 60% of the jawbreakers weigh more than 0.4 ounces, it is not unusual for a sample of 800 jawbreakers to contain 418 jawbreakers that weigh more than 0.4 ounces. This value falls within the expected range based on the company's claim.
Therefore, it would not be considered unusual for this sample of 800 jawbreakers to contain 418 that weigh more than 0.4 ounces according to Acme Candy Company's claim.